24x=28x^2

Solution for 24x=28x^2 equation:

24x=28x^2

We move all terms to the left:

24x-(28x^2)=0

determiningTheFunctionDomain
-28x^2+24x=0

a = -28; b = 24; c = 0;
Δ = b2-4ac
Δ = 242-4·(-28)·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-24}{2*-28}=\frac{-48}{-56}
=6/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+24}{2*-28}=\frac{0}{-56}
=0
$